Admirali
ITSD Engineer
Regjistruar: 07/01/2003
Vendbanimi: Durrės
Mesazhe: 2298
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Re: Need help badddd
Citim: Po citoj ato që tha Diellza04
Kam nje problem matematike qe shpresoj se do te me ndihmoni .
eshte anglisht dhe te them te drejten nuk e perktheja dot ne shqip.
The speed you were going is added to how much over the speed limit that speed is. The sum is then squared. The answer is the fine. Chris's fine for going 23 miles over the posted speed limit was $5041. How fast was he going and what was the posted speed limit?
Do t'jua kisha per nder te madh nqs mund te me ndihmonit.
Shume thanx
Atehere Chris po ecte me 71 mi/h, kurse shpejtesia e lejuar ishte 48 mi/h. Kjo eshte pergjigja. Persa i perket sesi zgjidhet problemi ja arsyetimi:
Ne baze te te dhenave te problemit, vlera e gjobes qe ti merr eshte shpejtesia qe ti ecen ne katror (The sum is then squared. The answer is the fine), dhe Chris mori nje gjobe prej $5041. Gjejme rrenjen katrore te kesaj gjobe, qe te na dale sesa shpejt po ecte Chris, dhe pergjigja eshte 71. Ketij numri i heqim 23 mi qe ai ecte mbi shpejtesine e lejuar, per te gjetur dhe kufirin maksimal. Pergjigja eshte 48.
Nqs e don ne forme ekuacioni:
X => Posted limit speed
X+23 => Chris's speed
5041 =>the fine
the equation is: (X+23)^2=5041
^2 mean "to the power of two"
You take the square root of both sides of equation:
X+23=71
X=48
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